How many moles of solute are contained in 200 milliliters of a 1 M solution?

1 Answer
anor277
May 29, 2016

Such a volume contains #0.200# #mol# of solute.

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#.

Typically, we perform the calculation: #C=n/V#, where #n# is the amount of solute in moles, #V# the volume of the solution in #"litres"#, and #C#, the concentration in #mol*L^-1#.

Given #C=n/V#, then #n# #=# #CxxV#.

Here, #n# #=# #200xx10^-3*Lxx1*mol*L^-1# #=# #0.200*mol#. This calculation is consistent dimensionally, as when #L# cancel, we get an answer in #mol#.

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