How many moles of H_2SO_4H2SO4 are present in 1.63 liters of a .954 M solution?

1 Answer
anor277
Apr 12, 2017

Here, there are 1.56*mol1.56⋅mol with respect to H_2SO_4H2SO4.........

Explanation:

By definition, "Concentration"="Moles"/"Volume"Concentration=MolesVolume, and thus by manipulating this expression, we get, "Volume"="Moles"/"Concentration"Volume=MolesConcentration, or, as we require here..............

"Moles"="Volume"xx"Concentration"Moles=Volume×Concentration; and so we calculate the product.........

1.63*Lxx0.954*mol*L^-1=1.63*cancelLxx0.954*mol*cancel(L^-1)

=1.56*mol of H_2SO_4.

Such a product is dimensionally consistent; we wanted an answer in moles and the product gave us one, which persuades us that we have done the right thing arithmetically.

What is the concentration with respect to H^+ or H_3O^+?

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