How many moles of #H_2# are needed to react with .80 mol of #N_2#? Chemistry Gases Gas Stoichiometry 1 Answer Meave60 Nov 12, 2015 #"2.4 mol H"_2"# are needed to react with #"0.80 mol N"_2"#. Explanation: Balanced Equation #"N"_2("g")+"3H"_2("g")##rarr##"2NH"_3("g")# Multiply the #"0.80 mol N"_2"# times the mole ratio between #"H"_2"# and #"N"_2"# so that moles #"N"_2"# cancel, leaving moles #"H"_2"#. #0.80cancel("mol N"_2)xx(3"mol H"_2)/(1cancel("mol N"_2))="2.4 mol H"_2"# Answer link Related questions How do you apply gas stoichiometry? How do you solve a gas law stoichiometry problem? How do you do gas stoichiometry problems at STP? When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... See all questions in Gas Stoichiometry Impact of this question 3407 views around the world You can reuse this answer Creative Commons License