How many moles of gas at 5.60 atm and 300 K will occupy a volume of 10.0 L?

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Answer 1 · 2015-12-19T13:24:20

#2.28# #"mol"#

Use the ideal gas law equation

#PV=nRT#

where

#P="pressure"=5.60# #"atm"#
#V="volume"=10.0# #"L"#
#n="moles"#
#R="ideal gas constant"=0.082# #("L atm")/("K mol")#
#T="temperature"=300# #"K"#

Since we want to find the amount of moles, we can rearrange the equation by dividing by #RT#.

#n=(PV)/(RT)#

#n=(5.60xx10.0)/(.082xx300)=2.28# #"mol"#