How many mL of a 2.00M $H_2SO_4$ are needed to provide .250 mole of $H_2SO_4$ ?

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Answer 1 · 2016-05-29T09:37:29

Over $100*mL$ .

$"Moles"$ $=$ $"Concentration"xx"Volume"$ . This can be appreciated dimensionally, i.e. $mol*L^-1xxL=mol!$ .

We require $0.250*mol$ , and so we divide the required number of moles by the concentration to get the volume:

$(0.250*cancel(mol))/(2.00*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)$ $=$ $??mL$

How many mL of a 2.00M H_2SO_4H_2SO_4 are needed to provide .250 mole of H_2SO_4H_2SO_4?