How many mL of a 2.00M #H_2SO_4# are needed to provide .250 mole of #H_2SO_4#?

1 Answer
anor277
May 29, 2016

Over #100*mL#.

Explanation:

#"Moles"# #=# #"Concentration"xx"Volume"#. This can be appreciated dimensionally, i.e. #mol*L^-1xxL=mol!#.

We require #0.250*mol#, and so we divide the required number of moles by the concentration to get the volume:

#(0.250*cancel(mol))/(2.00*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)# #=# #??mL#

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