# How many liters of a .88 M solution can be made with 25.5 grams of lithium fluoride (#LiF#)?

##### 1 Answer

May 16, 2016

#### Explanation:

The Molarity

For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

Li = 6.94

F = 19.0

LiF = 25.94 g/mole

Now we can take the the molarity and the moles and calculate the Liters of solution