How many grams of solute are needed to prepare 5.00 L of a o.250 M solution of Ca(NO_3)_2?

1 Answer
May 31, 2017

Over 400*g of solute are present..........

Explanation:

"Concentration"="Moles of solute"/"Volume of solution"

And thus..........

"moles of solute"="concentration"xx"volume"

=0.250*mol*cancel(L^-1)xx5.00*cancelL=2.50*mol

"Mass of solute"="moles"xx"molar mass"

=2.50*molxx164.09*g*mol^-1=??*g