How many grams of solute are needed to prepare 5.00 L of a o.250 M solution of #Ca(NO_3)_2#?

1 Answer
anor277
May 31, 2017

Over #400*g# of solute are present..........

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#

And thus..........

#"moles of solute"="concentration"xx"volume"#

#=0.250*mol*cancel(L^-1)xx5.00*cancelL=2.50*mol#

#"Mass of solute"="moles"xx"molar mass"#

#=2.50*molxx164.09*g*mol^-1=??*g#

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