How many grams of solute a contained in 2.5 liters of 3.0 molar aluminum nitrate solution?

1 Answer
anor277
Jun 4, 2017

Approx. 1.6*kg1.6⋅kg of solute............

Explanation:

"Concentration"="Moles of solute"/"Volume of solution"Concentration=Moles of soluteVolume of solution

And so to get the "moles of solute"moles of solute, we take the product........

"concentration"xx"volume"=3.0*mol*cancel(L^-1)xx2.5*cancel(L)=7.5*mol.

And to get the mass of "aluminum nitrate" we take the product,

"Molar quantity"xx"molar mass"=7.5*molxx213.03*g*mol^-1=??*g

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