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How many grams of potassium carbonate are needed to make 200 mL of a 2.5 M solution?

1 Answer

Mar 12, 2016

We need approx. $70$ $70$ $g$ $g$ of potassium carbonate.

Explanation:

$Concentration$ $"Concentration"$ $=$ $=$ $\frac{Moles of solute}{Volume of solution (L)}$ $"Moles of solute"/"Volume of solution (L)"$

Thus, $Moles of solute$ $"Moles of solute"$ $=$ $=$

$Concentration \times Volume of solution$ $"Concentration "xx" Volume of solution"$

$2.50 \cdot m o l \cdot L^{- 1} \times 0.200 \cdot L$ $2.50*mol*L^-1xx0.200*L$ $=$ $=$ $0.500 \cdot m o l$ $0.500*mol$

$0.500*cancel(mol)xx138.21*g*cancel(mol^-1)" potassium carbonate"$ $=$ $??g" potassium carbonate"$

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