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How many grams of oxygen are required to produce 55.6 g water vapor?

1 Answer

Jul 10, 2016

Approx. #50*g# dioxygen are necessary.

Explanation:

#H_2(g) + 1/2O_2(g) rarr H_2O(g)#

#"Moles of water"# #=# #(55.6*g)/(18.01*g*mol^-1)# #=# #3.09*mol#

If there are #3.09*mol# of water, then clearly, there were #1.54*mol# #O_2(g)# as a reactant.

And thus #"mass of oxygen"# #=# #1.54*molxx32.00*g*mol^-1#.

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