How many grams of $H_3PO_4$ are in 175 mL of a 3.5 M solution of $H_3PO_4$ ?

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Answer 1 · 2018-04-04T00:32:31

Around $60$ grams.

We have a $3.5 \ "M"$ solution of phosphoric acid with $175 \ "mL$ of it in there. This means that there are:

$(3.5 \ "mol")/(color(red)cancelcolor(black)"L")*0.175color(red)cancelcolor(black)"L"=0.6125 \ "mol"$

So, there exist $0.6125$ moles of phosphoric acid here.

Phosphoric acid has a molar mass of $97.994 \ "g/mol"$ .

So here, the mass is:

$0.6125color(red)cancelcolor(black)"mol"*(97.994 \ "g")/(color(red)cancelcolor(black)"mol")~~60 \ "g"$

How many grams of H_3PO_4H_3PO_4 are in 175 mL of a 3.5 M solution of H_3PO_4H_3PO_4?