How many grams of #CO_2# and grams of #H_2O# are produced when 52.0 g #C_2H_2# burns in oxygen?

Question

3214 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-20T18:38:13

#H-C-=C-H(g) + 5/2O_2(g) rarr 2CO_2(g) + H_2O#

#H-C-=C-H(g) + 5/2O_2(g) rarr 2CO_2(g) + H_2O(l)#

#"Moles of acetylene"# #=# #(52.0*g)/(26.04*g*mol^-1)# #=# #2*mol#

Given the molar equivalence, #4*molxx44.0*g*mol^-1# #CO_2# are produced, as well as #36.0*g# water.