How many f orbitals are present in n=3?

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How many f orbitals are present in n=3?

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Answer 1 · 2015-11-06T01:00:16

Zero.

Explanation:

As you know, the number of orbitals you get per energy shell is given by the equation

$no. of orbitals = n^{2}$ $color(blue)("no. of orbitals" = n^2)" "$ , where

$n$ $n$ - the energy level, also known as energy shell

Now, the third energy level, characterized by $n = 3$ $n=3$ , will have a total of

$no. of orbitals = 3^{2} = 9$ $"no. of orbitals" = 3^2 = 9$

orbitals. But how many of these orbitals will be f-orbitals?

As it turns out, none.

Each energy level contains a number of subshells given by the angular momentum quantum number, $l$ $l$ , which can take values ranging from $0$ $0$ to $n - 1$ $n-1$ .

$l = 0, 1, 2, ..., n-1$

This means that the third energy level will have a total of three subshells

one s-subshell, for which $l=0$

one p-subshell, for which $l=1$

one d-subshell, for which $l=2$

The f-subshell, for which $l=3$ , doesn't come around until the fourth energy level, $n=4$ .

Therefore, you can say that the third energy level contains no f-orbitals since it contains no f-subhsell.

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How many f orbitals are present in n=3?

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