How do I solve this? Thank you!

Question

↳Redirected from "What is the oxidation state of copper in #"CuSO"_4#?"

2516 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-08T17:42:38

#x= 2^13 = 8,192#

The logs are all to the same base.

#color(blue)(5)log_2 4 +log_2 8 = log_2 x" "larr# use the power law

#log_2 4^color(blue)(5) +log_2 8 = log_2 x#

If logs are being added, numbers are multiplied...

#log_2 (4^5 xx 8) = log_2 x" "larr# change to powers of 2

#log_2 ((2^2)^5 xx 2^3) = log_2 x#

#log_2 (2^10 xx 2^3) = log_2 x#

#log_a B = log_a C hArr B=C#

#2^13 =x#