# How fast will an object with a mass of 16 kg accelerate if a force of 4 N is constantly applied to it?

Mar 10, 2018

$a = 0.25 \frac{m}{s} ^ 2$

#### Explanation:

We can use the equation:

Force $=$ mass $\cdot$ acceleration

Or:

$F = m a$

Here, $F = 4 N$
Here, $m = 16 k g$

Thus, we can input the values:

$4 = 16 a$

Solve for $a$:

$16 a = 4$

$\frac{16 a}{16} = \frac{4}{16}$

$a = \frac{4}{16}$

$a = 0.25 \frac{m}{s} ^ 2$

Thus, solved.

Mar 10, 2018

I get $0.25 \setminus {\text{m/s}}^{2}$.

#### Explanation:

We use Newton's second law of motion, which states that

$F = m a$

where $m$ is the mass of the object in kilograms, $a$ is the acceleration in ${\text{m/s}}^{2}$.

We need to solve for acceleration, so we arrange the equation into:

$a = \frac{F}{m}$

Plugging in the values, we get

$a = \left(4 \setminus \text{N")/(16 \ "kg}\right)$

Recall that $1 \setminus {\text{N"=1 \ "kg"*"m/s}}^{2}$. So, we got

$a = \left(4 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{kg"*"m/s"^2)/(16color(red)cancelcolor(black)"kg}}}}\right)$

$= 0.25 \setminus {\text{m/s}}^{2}$

So, the object will accelerate at $0.25 \setminus {\text{m/s}}^{2}$.