How do you write `y - 6 = 4(x + 3)` in standard form?

Warning: standard form when not qualified and applied to a linear relation usually means `color(blue)("linear standard form")` which is `Ax+By=C` with `A,B,C in ZZ, and A >= 0`

However this question was asked under "Polynomials in Standard Form", so I have assumed you want something of the form:
`color(white)("XXX")color(red)(y= "polynomial standard form expression")`

A `color(red)("polynomial standard form expression")` arranges the variable terms (typically with `x` used as the variable) win descending sequence of exponents: `color(red)(a_nx^n+a_(n-1)x^(n-1)+...+a_2x^2+a_1x^1+a_0x^0)`

Given
`color(white)("XXX")y-6=4(x+3)`
we can expand the right side:
`color(white)("XXX")y-6 = 4x+12`
then adding `6` to both sides:
`color(white)("XXX")y=color(red)(4x+18)`

It would be unusual, but you could write this to make the `color(red)("polynomial standard form")` explicit:
`color(white)("XXX")y=color(red)(4 * x^1+18 * x^0)`

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Without going into the details of derivation, if you wanted the `color(blue)(" linear standard form")` is would be
`color(white)("XXX")color(blue)(4x-y=-18)`