How do you write $y+4=\frac{-2}{3}(x+6)$ in slope intercept form?

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Answer 1 · 2014-10-26T10:34:02

The key is to isolate $y$ .

$y+4=-{2}/{3}(x+6)$

by distributing $-2/3$ to $x$ and $6$ ,

$Rightarrowy+4=-2/3x-4$

by subtracting $4$ ,

$Rightarrow y=-2/3x-8$ ,

I hope that this was helpful.

How do you write y+4=\frac{-2}{3}(x+6)y+4=\frac{-2}{3}(x+6) in slope intercept form?