How do you write #y+3=-1/3(2x+6)# in slope intercept form?

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Answer 1 · 2017-04-29T20:18:48

See the solution process below:

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Solving this for #y# gives:

#y + 3 = color(red)(-1/3)(2x + 6)#

#y + 3 = (color(red)(-1/3) * 2x) + (color(red)(-1/3) * 6)#

#y + 3 = -2/3x + (-6/3)#

#y + 3 = -2/3x - 6/3#

#y + 3 = -2/3x - 2#

#y + 3 - 3 = -2/3x - 2 - 3#

#y + 0 = -2/3x - 5#

#y = color(red)(-2/3)x - color(blue)(5)#