How do you write #y =-2x^2 + 12x - 13# in vertex form and identify the vertex?

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Answer 1 · 2015-05-24T17:58:44

The vertex form is:

#y-y_v=a(x-x_v)^2#.

So:

#y=-2(x^2-6x)-13rArr#

#y=-2(x^2-6x+9-9)-13rArr#

#y=-2(x^2-6x+9)+18-13rArry=-2(x-3)^2+5rArr#

#y-5=-2(x-3)^2#, and the vertex is #V(3,5)#.