How do you write $Y=2/3x-2$ in standard form?

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Answer 1 · 2016-11-27T10:07:59

$2x - 3y = 6$

Standard form: Ax + By = C
Just take 2/3x to the other side.

So the answer would be $-2/3x + y = -2$

But not yet the final answer... In standard form $x$ can't be negative and A, B and C need to be an integers (whole numbers)

(I multiplied the whole equation by -3)

$2x-3y = 6$

So the final answer would be: $2x -3y = 6$

How do you write Y=2/3x-2Y=2/3x-2 in standard form?