How do you write $y = - \frac{2}{3} x + 1$ $y=-2/3x+1$ in standard form?

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Answer 1 · 2015-05-05T12:54:01

The "standard form" of a linear equation is (normally considered to be)
$A x + B y = C$ $Ax+By=C$
(with $x$ $x$ a non-negative integer)

$y = - \frac{2}{3} x + 1$ $y=-2/3x+1$

$(\frac{2}{3}) x + (1) y = 1$ $(2/3)x+(1)y = 1$

$2 x + 3 y = 3$ $2x+3y = 3$

How do you write y=−23x+1y=-2/3x+1 in standard form?