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How do you write #x = log_by# in exponential form?

1 Answer

Aug 30, 2015

#b^x = y#

Explanation:

#g(y) = log_b(y)# is by definition the inverse of #f(x) = b^x#,

So just apply the exponentiation given by this function #f(x)# to both sides to get:

#b^x = b^(log_b(y)) = y#

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