How do you write the Vertex form equation of the parabola #y = x^2-6x+8#?

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How do you write the Vertex form equation of the parabola #y = x^2-6x+8#?

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Answer 1 · 2016-05-08T12:29:46

#y = (x - 3)^2 - 1#

Explanation:

#y = x^2 - 6x + 8#
x-coordinate of vertex:
#x = -b/(2a) = 6/2 = 3#
y-coordinate of vertex:
y(3) = 9 - 18 + 8 = -1
Vertex (3, -1)
Vertex form:
#y = (x - 3)^2 - 1#

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How do you write the Vertex form equation of the parabola #y = x^2-6x+8#?

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