How do you write the slope of the line tangent to #g(x)=5-x^2# at the point (2,1)? Calculus Derivatives Tangent Line to a Curve 1 Answer VinÃcius Ferraz May 29, 2017 #-4# Explanation: #g(2) = 1# #g'(x) = -2x => g'(2) = -4# The end. #y = ax + b, a = -4, y(2) = 1# #1 = -4 * 2 + b => b = 9# #y = -4x + 9# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1379 views around the world You can reuse this answer Creative Commons License