How do you write the slope of the line tangent to #g(x)=3/2x+1# at the point (-2,2)?

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How do you write the slope of the line tangent to #g(x)=3/2x+1# at the point (-2,2)?

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Answer 1 · 2016-11-22T22:26:29

#3/2#

Explanation:

#g(x)# is a straight line and comparing with the standard equation #y=mx+c# we see that #m=3/2#, so the gradient of the tangent is constant and is #3/2# everywhere on #g#

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How do you write the slope of the line tangent to #g(x)=3/2x+1# at the point (-2,2)?

1 Answer

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