How do you write the slope intercept form of the line #11x-8y=-48#?

1 Answer
Jim G.
Feb 12, 2017

#y=11/8x+6#

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

#"Rearrange " 11x-8y=-48" into this form"#

subtract 11x from both sides of the equation.

#cancel(11x)cancel(-11x)-8y=-11x-48#

#rArr-8y=-11x-48#

divide all terms on both sides by - 8

#(cancel(-8) y)/cancel(-8)=(-11)/(-8)x-48/(-8)#

#rArry=11/8x+6larrcolor(red)" in slope-intercept form"#

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