How do you write an equation for a line with m=3.5 and #f(-2)=1#?

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How do you write an equation for a line with m=3.5 and #f(-2)=1#?

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Answer 1 · 2018-06-25T13:12:25

#f(-2)=1# means that a point exists at #(-2,1)#. Using our formula for the slope-intercept form of a line, #y=mx+b#, we can just plug in values and find the equation:

#1=3.5(-2)+b#
#1=-7+b#
#8=b#
#y=3.5x+8# or #y=7/2 x+8#

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How do you write an equation for a line with m=3.5 and #f(-2)=1#?

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