How do you write the slope intercept form for (-2,9) and (1,6)?

1 Answer
Alan P.
Dec 9, 2016

#y=(-1)x+7#

Explanation:

A line through the points #(-2,9)# and #(1,6)#
has a slope of #color(magenta)m=(Deltay)/(Deltax)=(9-6)/(-2-1)=3/(-3)=color(magenta)(-1)#
and
using the point #(1,6)#
a slope point form of
#color(white)("XXX")(y-6)=color(magenta)(-1)(x-1)#
The requested slope-intercept form must look like
#color(white)("XXX")y=color(magenta)mx+color(blue)b#

#ycolor(green)(-6)=color(magenta)(-1)(x-1)#
#color(white)("XXX")rArr y=color(magenta)(-1)x+1color(green)(+6)#
or
#color(white)("XXX")y=color(magenta)(-1)x+color(blue)7#

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