How do you write the quadratic in vertex form given #y=x^2+4x-7#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer George C. May 10, 2015 #y = x^2+4x-7 = (x+2)^2 - 11# In general, for #y = ax^2 + bx + c#, the #x# coordinate of the vertex is #-b/(2a)#, and the vertex form is: #y = a(x + b/(2a))^2 + (c - b^2/(4a))# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2008 views around the world You can reuse this answer Creative Commons License