How do you write the quadratic in vertex form given #y= x^2 - 12x + 20 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. May 13, 2015 #(-b/2a) = -12/2 = 6# #f(-b/2a) = f(6) = 36 - 72 + 20 = -16# Factored form:# f(x) = (x - 6)^2 - 16# Check: #Develop f(x) = (x^2 - 12x + 36 - 16 = x^2 - 12x + 20#. Correct Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3205 views around the world You can reuse this answer Creative Commons License