How do you write the quadratic in vertex form given #y=2x^2-10x+5#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. May 9, 2015 Vertex form# f(x) = (x - b/(2a))^2 + f(-b/(2a))# #-b/2a = 10/4 = 5/2# #f(5/4) = 2(25/4) - 10(5/2) + 5 = -15/2# Vertex form #f(x) = (x - 5/2)^2 - 15/2# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2548 views around the world You can reuse this answer Creative Commons License