How do you write the inequality and solve given "three times a number increased by 8 is no more than the number decreased by 4"?

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Answer 1 · 2017-10-06T09:43:44

#a <= -6#

Let the number be #a#,

Given that:
Three times a number increased by #8 => 3a +8#

'is no more than' means it can be the same as or less than the number decreased by #4# :

#3a +8 <= a-4#

Solving :
Take the terms with variable #a# to left hand side and keep the other terms on right hand side. Apply transposition rules:

#3a - a <= -8-4#

#2a <= -12#

#a <= -6#