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How do you write the exponential notation for #log_8 1 = x#?

1 Answer

Dec 26, 2015

#8^x = 1#

Explanation:

For any positive number #b != 1#, #log_b(x)# and #b^x# are inverse functions of one another.

So given #log_8(1) = x# apply exponentiation using #8# on both sides to find:

#8^x = 8^(log_8(1)) = 1#

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