How do you write the explicit formula for the sequence 2,8,32,128,...?

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How do you write the explicit formula for the sequence 2,8,32,128,...?

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Answer 1 · 2016-03-11T12:35:08

#2^(2n-1)#

Explanation:

#2^1,2^3,2^5,2^7............#

Here the power of 2 is in AP whose first term =1 and common difference is 2, so nth term will be# 1+(n-1)xx2=2n-1#
Hence nth term of given series is #2^(2n-1)#

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How do you write the explicit formula for the sequence 2,8,32,128,...?

1 Answer

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