How do you write the equation #y+6=3/2(x-4)# in standard form?

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Answer 1 · 2017-04-22T23:19:07

#y=3/2x-12#

Standard form is #y=ax^2+bx+c#, so our first job is to let #y# be the only value on the side of the equal sign:

#y+6=3/2(x-4)#

subtract #6# on both sides

#y=3/2(x-4)-6#

Now distribute the #3/2#

#y=3/2x-6-6#

combine like-terms

#y=3/2x-12#