How do you write the equation #y-6=1.3(x+7)# in standard form?

1 Answer
Jim G.
Mar 12, 2017

#13x-10y=-151#

Explanation:

The equation of a line in #color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.

distribute the bracket and rearrange into this form.

#y-6=1.3x+9.1#

#rArry=1.3x+15.1#

We now require to multiply through by 10 as we require the coefficients to be integers.

#rArr10y=13x+151#

subtract 10y from both sides.

#0=13x-10y+151#

subtract 151 from both sides.

#-151=13x-10y#

#rArr13x-10y=-151larrcolor(red)" in standard form"#

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