# How do you write the equation #y+4=-1/3(x-12)# in standard form?

##### 2 Answers

x+3y=0#

#### Explanation:

The equation of a line in

#color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

where A is a positive integer and B, C are integers.

#"Rearrange " y+4=-1/3(x-12)" into this form"#

#"multiply ALL terms by 3 to eliminate the fraction"#

#3y+12=(cancel(3)^1xx-1/cancel(3)^1(x-12))#

#rArr3y+12=-x+12#

#"add x to both sides"#

#x+3y+12=cancel(-x)cancel(+x)+12#

#rArrx+3y+12=12#

#"subtract 12 from both sides"#

#x+3ycancel(+12)cancel(-12)=12-12#

#rArrx+3y=0larrcolor(red)" in standard form"#

See the entire solution process below:

#### Explanation:

The standard form of a linear equation is:

Where, if at all possible,

First, multiply each side of the equation by

Now, subtract