How do you write the equation #y+1/4=-3(x+1/2)# in slope intercept form?

Related questions

• How do you determine the #(x,y)# point given #f(x)=y#?
• How do you evaluate functions?
• How do you write an equation for a line with m=3.5 and #f(-2)=1#?
• What are the two points if you are given #f(-1)=2# and #f(0)=-6#?
• How do you write an equation for a line given #f(-1)=1# and #f(1)=-1#?
• How do you write an equation for a line given #m=-7# and #f(2)=-1#?
• How do you determine the slope given #f(-4)=2# and #f(0)=3#?
• How do you write an equation of the line with slope -3 and y-intercept (0,-5)?
• How do you find the slope-intercept form of the equation of the line that passes through (-2,...
• How do you write the slope intercept form of the equation of the line through the given point...