How do you write the equation of the parabola in vertex form given vertex is at (-1, 17) and the parabola passes through the point (0, 6)?

1 Answer
Feb 21, 2016

#y = - 11 (x + 1 )^2 + 17 #

Explanation:

The equation of a parabola in vertex form is

#y = a(x - h )^2 + k#
#" where (h , k) are the coordinates of vertex "#

here the vertex = (-1 , 17 ) and so equation is

# y = a(x + 1 )^2 + 17#

Since the point (0 , 6) lies on the parabola it will satisfy the equation and by substituting the coordinate point , will allow a to be found.

hence # 6 = a(0+1)^2 + 17 → 6 = a +17 → a = - 11#

#rArr y = -11(x + 1 )^2 + 17#