How do you write the equation of the parabola in vertex form given vertex is (2,3) and the zeros are x=0 and x=4?

1 Answer
May 19, 2017

#y=-3/4(x-2)^2+3#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
where ( h , k ) are the coordinates of the vertex and a is a constant.

#"here " (h,k)=(2,3)#

#rArry=a(x-2)^2+3#

#"to find a, substitute either of the 2 zeros into the equation"#

#"using " (4,0)#

#0=a(4-2)^2+3#

#rArr4a+3=0rArra=-3/4#

#rArry=-3/4(x-2)^2+3larrcolor(red)" in vertex form"#
graph{-3/4(x-2)^2+3 [-10, 10, -5, 5]}