How do you write the equation $log_8 (4)=2/3$ in exponential form?

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Answer 1 · 2017-01-04T15:55:20

$4=8^(2/3)$

If $log _b a = k$ , its inverse is $a=b^k$ .

Here, the inverse of $log_8 4=2/3$ , the inverse is $4=8^(2/3)$ .

Some more examples:

RELATION INVERSE (for the same relation)

$y=ln x to x=e^y$

$y=log x to x=10^y$

$2=log_16 256 to 256=16^2$

How do you write the equation log_8 (4)=2/3log_8 (4)=2/3 in exponential form?