How do you write the equation #log_7 (1/2401)=-4# into exponential form?

1 Answer
Shell
Dec 20, 2016

#7^-4=1/2401#

Explanation:

Write #log_7(1/2401)=-4# as an exponential.

Use the rule #log_bx=a color(white)(aa)=> color(white)(aa)x=b^a#

#log_7(1/2401)=-4color(white)(aa)=>color(white)(aa)7^-4=1/2401#

Note that the #7# is the base of the log and the base of the exponential. And, the "answer" to a log equation is the exponent of the exponential.

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