How do you write the equation in slope intercept form given (1,-3) with x-intercept = -1?

1 Answer
David Drayer · EZ as pi
Aug 9, 2016

#y = mx + b # where #y = -3/2x -1 1/2#

Explanation:

Explanation

Explanation:

In # y = mx + b# The slope intercept form
m = the slope think m = mountain slope
b = the y-intercept think b = beginning starting point.
m ; the slope = the change in y divided by the change in x

# (y_2 - y_1)/(x_2 - x_1)# = m

Substitute -3 for #y_2# and 0 for #y_1# ( y is zero at the x intercept)
Substitute 1 for #x_2# and -1 for #x_1# ( -1 is the x intercept)

# ( -3 - 0) / { 1 - ( -1 ) # = m

m = # -3/( +2)#

Now, to find the y-intercept remember #x=0# at the y-intercept.
So one point is ( 0, b) and a second point is ( 1,-3)

#(b - ( -3))/( 0 - 1 ) = -3/2#

#(b+3)/(-1) = (-3)/2#

multiplying both sides by -1 gives

#b + 3 = 3/2#
subtracting -3 from both sides gives

#b = 3/2 - 3#

#b = - 3/2#

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