How do you write the equation #6x-8y=21# in polar form?
1 Answer
Nov 6, 2016
Explanation:
To convert from
#color(blue)"cartesian to polar form"#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(x=rcostheta , y=rsintheta)color(white)(2/2)|)))# substitute into the equation.
#rArr6(rcostheta)-8(rsintheta)=21#
#rArr2r(3costheta-4sintheta)=21#
#rArrr=21/(2(3costheta-4sintheta))#
