How do you write the equation $6^-2=1/36$ into logarithmic form?

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Answer 1 · 2018-04-29T20:21:11

$log_6(1/36)=-2$

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)log_b x=nhArrx=b^n$

$"here "b=6,n=-2" and "x=1/36$

$rArrlog_6(1/36)=-2hArr6^-2=1/36$

How do you write the equation 6^-2=1/366^-2=1/36 into logarithmic form?