How do you write the equation #3x+2y-5=0# in polar form?

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Answer 1 · 2017-05-06T12:30:33

#r=5/(3costheta+2sintheta)#

for polar coordinates we use the relations

#x^2+y^2=r^2

#x=rcostheta#

#y=rsintheta#

#3x+2y-5=0#

becomes

#3rcostheta+2rsintheta-5=0#

#r(3costheta+2sintheta)=5#

#r=5/(3costheta+2sintheta)#