How do you write the equation $36^(3/2)=216$ into logarithmic form?

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Answer 1 · 2017-01-25T04:02:33

$36^(3/2)=216 <=> log_36(216)=3/2$

We can convert an exponential expression into a logarithmic one by this general formula:

$a^b=c <=> log_a(c)=b$

On the left, we can say that the number a, multiplied by itself b times, gives a result of c.

On the right, we can say that the number a, to achieve the number c, needs to be multiplied by itself b times.

We can therefore convert:

$36^(3/2)=216 <=> log_36(216)=3/2$

How do you write the equation 36^(3/2)=21636^(3/2)=216 into logarithmic form?