How do you write the cartesian equation for #r=1+3sinx#? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer sankarankalyanam Jul 9, 2018 As below. Explanation: #r = 1 + 3 sin theta# #x = r cos theta, y = r sin theta, r = sqrt(x^2 + y^2)# #sqrt(x^2 + y^2) = 1 + 3 * y/sqrt(x^2 + y^2)# #x^2 + y^2 = sqrt(x^2 + y^2) + 3y# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 2903 views around the world You can reuse this answer Creative Commons License