How do you write the cartesian equation for #r=1-3cosx#?

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How do you write the cartesian equation for #r=1-3cosx#?

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Answer 1 · 2018-07-09T07:08:32

As below

Explanation:

#x = r cos theta, y = r sin theta, x^2+y^2=r^2#

#r = 1 - 3 cos x#

#sqrt(x^2 + y^2) = 1 - (3 x) / sqrt(x^2 + y^2)#

#x^2 + y^2 = sqrt(x^2 + y^2) - 3x#

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How do you write the cartesian equation for #r=1-3cosx#?

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