How do you write # log x = y# in exponential form?

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How do you write # log x = y# in exponential form?

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Answer 1 · 2015-10-05T10:07:48

#x= e^y#

Explanation:

Simply consider the fact that, if #log(x)=y#, than also #e^{log(x)}=e^y# must hold. Now use the fact that the exponential function #e^x# is the inverse of the logarithmic function #log(x)#, which means that #e^{log(x)}=x#, and thus the solution.

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How do you write # log x = y# in exponential form?

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